Discussion :: Engineering Mechanics
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The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is
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A.
\( \frac { h } { kG^{2} + h^{2} } \) |
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B.
\( \frac { kG^{2} + h^{2} } { h } \) |
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C.
\( \frac{ h^{2} } { kG^{2} + h^{2} } \) |
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D.
\( \frac{ kG^{2} + h^{2} } { h^{2} } \) |
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Answer : Option B
Explanation :
No answer description available for this question.
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