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  1. What will be the output of the program?

    class PassA
     {         
         public static void main(String [] args) 
         {                                   
           passA p = new PassA();            
           p.start();              
         }  
         void start()
         {      
           long [] a1 = {3,4,5}; 
           long [] a2 = fix(a1);  
           System.out.print(a1[0] + a1[1] + a1[2] + " ");
           System.out.println(a2[0] + a2[1] + a2[2]);
         }   
         long [] fix(long [] a3)   
         {
            a3[1] = 7;     
            return a3;     
         }
     } 
    

     

  2. A.

    12 15

    B.

    15 15

    C.

    3 4 5 3 7 5

    D.

    3 7 5 3 7 5

    View Answer

    Workspace

    Answer : Option B

    Explanation :

    Output: 15 15

    The reference variables a1 and a3 refer to the same long array object. When the [1] element is updated in the fix() method, it is updating the array referred to by a1. The reference variable a2 refers to the same array object.

    So Output: 3+7+5+" "3+7+5

    Output: 15 15 Because Numeric values will be added

     

     

     


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