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Discussion :: Exceptions

  1. What will be the output of the program?

      class Exc0 extends Exception { }
  class Exc1 extends Exc0 { } /* Line 2 */    
  public class Test 
  {      
    public static void main(String args[])      
  {       
     try       
     {          
        throw new Exc1(); /* Line 9 */              
     }    
     catch (Exc0 e0) /* Line 11 */  
     {          
     System.out.println("Ex0 caught");          
     }      
     catch (Exception e)       
    {                 
    System.out.println("exception caught");              
    }     

  } 

 }

     

    2. A.

    Ex0 caught
    B.

    exception caught
    C.

    Compilation fails because of an error at line 2.
    D.

    Compilation fails because of an error at line 9.

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    Answer : Option A

    Explanation :

    An exception Exc1 is thrown and is caught by the catch statement on line 11. The code is executed in this block. There is no finally block of code to execute.

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