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  1. What will be the output of the program?

    public class RTExcept 
     {    
       public static void throwit ()   
       {       
          System.out.print("throwit ");         
          throw new RuntimeException();
       }   
       public static void main(String [] args) 
       }    
         try       
        {         
            System.out.print("hello ");             
            throwit();     
        }       
        catch (Exception re )     
         {             
            System.out.print("caught ");        
         }        
    finally        
        {          
           System.out.print("finally ");        
        }      
       System.out.println("after ");    
      } 
    } 
    

  2. A.

    hello throwit caught

    B.

    Compilation fails

    C.

    hello throwit RuntimeException caught after

    D.

    hello throwit caught finally after

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    Answer : Option D

    Explanation :

    The main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.

    A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.

     


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