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Discussion :: Exceptions

  1. What will be the output of the program?

     public class X 
 {     
  public static void main(String [] args)     
  {       
     try        
     {          
         badMethod();                 
         system.out.print("A");  
     }         
     catch (Exception ex)      
     {            
         System.out.print("B");        
   }        
  finally       
   {          
       System.out.print("C");    
     }         
    System.out.print("D");    
    }      
    public static void badMethod()  
    {          
       throw new Error(); /* Line 22 */   
    }  
}

     

    2. A.

    ABCD
    B.

    Compilation fails.
    C.

    C is printed before exiting with an error message.
    D.

    BC is printed before exiting with an error message.

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    Answer : Option C

    Explanation :

    Error is thrown but not recognised line(22) because the only catch attempts to catch an Exception and Exception is not a superclass of Error. Therefore only the code in the finally statement can be run before exiting with a runtime error (Exception in thread "main" java.lang.Error).

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