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  1. Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be

    2. A.

     2 : 16 : 2
    B.

     2 : 16 : 1
    C.

     1 : 16 : 2
    D.

     1 : 1 : 1

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    Answer : Option C

    Explanation :

    Convert the mass into moles (use the formula n=m/Mr)
    m = mass and Mr = Molecular weights
    Molecular weights are 32(Oxygen), 2(Hydrogen), and 16(Methane), respectively.
    Since the masses are equal, you can take the mass as x. So, the number of moles would be:
    n(O2) = x/32
    n(H2) = x/2
    n(CH4) = x/16
    The ratio of their volumes is (O2) : (H2) : (CH4) = 1 : 16 : 2

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