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  1. If D is diameter of circular waveguide the cutoff wave-length for TE11 mode is equal to

  2. A.
    1.706 D
    B.
    2.11 D
    C.
    0.82 D
    D.
    0.41 D

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    Answer : Option A

    Explanation :

    Some applications require dual polarization capability. Circular waveguide has this capability.

    These analysis uses cylindrical coordinates.

    In circular waveguide TE11 mode has the lowest cut off frequency and is the dominant mode.

    If D is diameter of waveguide

    λc = 1.706 D for TE11 mode

    λc = 1.029 D for TE21 mode

    λc = 0.82 D for TE01 mode

    λc = 1.306 D for TM01 mode.


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