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  1. You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?

    2. A.

     192.168.192.15
    B.

     192.168.192.31
    C.

     192.168.192.63
    D.

     192.168.192.127

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    Answer : Option A

    Explanation :

    A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.

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