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Discussion :: Chemical Engineering Thermodynamics

  1. Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg . K, entropy of saturated vapour = 7.2234 kJ/kg. K) The exit condition of steam is

    2. A.

     Superheated vapour
    B.

     Partially condensed vapour with quality of 0.9
    C.

     Saturated vapour
    D.

     Partially condensed vapour with quality of 0.1

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    Answer : Option A

    Explanation :

    For an isentropic process s initial=s final (exit)
    ⇒6.65=Sliq+x(Sliq− Sv)⇒6.63=1.4336+x(7.2234−1.4336)⇒x=0.9
    So, we are getting partially condensed vapour with quality = 0.9.

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