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Discussion :: Chemical Engineering Thermodynamics

  1. The internal energy of an ideal gas does not change in a reversible __________ process.

    2. A.

     Isothermal
    B.

     Adiabatic
    C.

     Isobaric
    D.

     Isometric

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    Answer : Option A

    Explanation :

    We know for an ideal gas the internal energy is given by:
    Actually the internal energy (U) of any substance is a function of
    dU=CvdT−[P+T((∂V∂T)p(∂V∂P)T)dV]For an ideal gas, PV=RTSo, (∂V∂T)p=RPand (∂V∂P)T=−RTP2Hence, dU=CvdT
    So, in case of isothermal process the internal energy remains constant.

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