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  1. In a working refrigerator, the value of COP is always

  2. A.

     0

    B.

     < 0

    C.

     < 1

    D.

     > 1

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    Answer : Option D

    Explanation :

    We know COP of a refrigerator
    $$\eqalign{ & = \frac{{{\text{Cooling effect}}}}{{{\text{Work taken}}}} \cr & = \frac{{{Q_L}}}{{{W_{net}}}} \cr & = \frac{{{Q_2}}}{{{Q_1} - {Q_2}}} \cr} $$
    For a reversible refrigerator COP $$ = \frac{{{T_2}}}{{{T_1} - {T_2}}}$$
    Since $${T_1} - {T_2} < {T_2}$$
    So COP is always greater than zero.


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