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  1. What is the degree of freedom for two mis-cible (non-reacting) substances in vapor-liquid equilibrium forming an azeotrope?

    2. A.

     0
    B.

     1
    C.

     2
    D.

     3

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    Answer : Option C

    Explanation :

    The given number of component =2
    Given number of phases =2
    We know, degree of freedom (number of independent variables) =C−ϕ+2
    (assuming no reaction taking place)
    f=2−2+2=2
    And since under azeotropic conditions the composition of a component in both the phases remains same one of the independent variable becomes dependent and hence the degree of freedom reduces to 1.

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