Discussion :: Chemical Engineering Thermodynamics
- If the internal energy of an ideal gas decreases by the same amount as the work done by the system, then the
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A.
Process must be isobaric |
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B.
Temperature must decrease |
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C.
Process must be adiabatic |
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D.
Both B and C |
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Answer : Option D
Explanation :
By first law of thermodynamics we can say δQ=dU+δW
⇒ for the internal energy and work to be same in magnitude we can say that heat transfer has to be zero δQ=0
So the process is adiabatic and given the system is ideal gas and its internal energy is decreasing so, we can say that temperature decreases since the internal energy of a substance is solely dependent of temperature.
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