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Discussion :: Chemical Engineering Thermodynamics

  1. In a reversible process

    2. A.

     Tds = dE + dW
    B.

     DE - dW = Tds
    C.

     DW - dE = Tds
    D.

     Tds - dW + dE >0

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    Answer : Option A

    Explanation :

    From second law of thermodynamics :
    TdS⩾δQ⇒TdS⩾dU+δW
    For an irreversible process TdS−dU−δW>0
    And for an reversible process TdS−dU−δW=0

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