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Discussion :: Chemical Engineering Thermodynamics

  1. Grams of butane (C₄H₁₀) formed by the liquefaction of 448 litres of the gas (measured at (STP) would be

    2. A.

     580
    B.

     640
    C.

     1160
    D.

     Data insufficient; can't be computed

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    Answer : Option C

    Explanation :

    At S.T.P 1 mole of any gas occupies 22.4ltrs
    Given 448ltrs   so, number of moles = 44822.4 =20
    We know number of moles = weightgram moleculear weight     (molecular weight of C4H10=58)
    So, 20= weight58
    Hence weight of C4H10=1160

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