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Discussion :: Chemical Engineering Thermodynamics

  1. For an isothermal process, the internal energy of a gas

    2. A.

     Increases
    B.

     Decreases
    C.

     Remains unchanged
    D.

     Data insufficient, can't be predicted

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    Answer : Option C

    Explanation :

    The internal energy (U) is a function of

    dU=CvdT−[P+T{(∂V∂T)p(∂V∂P)T}dV]

    For an ideal gas, PV=RT

    So, (∂V∂T)p=RP and(∂V∂T)T=−RTP2

    Hence, dU=CvdT
    So, for an ideal gas if it undergoing isothermal change (dT=0)⇒dU=0
    So, the questioned should be changed and should be mentioned for an ideal gas.

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