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  1. A closed system is cooled reversibly from 100°C to 50°C. If no work is done on the system

    2. A.

     Its internal energy (U) decreases and its entropy (S) increases
    B.

     U and S both decreases
    C.

     U decreases but S is constant
    D.

     U is constant but S decreases

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    Answer : Option B

    Explanation :

    Since here heat is taken from the system Q=−ve
    From second law of thermodynamics TdS≥δQ
    Since given reversible process TdS=δQ
    ⇒dS=−ve
    From first law of thermodynamics
    δQ=dU⇒dU=−ve

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