Discussion :: Surds and Indices
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\( \frac { 1 } {1+X(b-a)+X(c-a) } \)+\(\frac { 1 } { 1+X(a-b)+X(c-b) }+ \)\(\frac { 1 } {1+X(b-c)+X(a-c)}=?\)
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Answer : Option B
Explanation :
Given Exp \(= \frac {1} { (1+ \frac { x^b } { x^a } + \frac { x^c } { x^a }) } + \frac {1} { (1+ \frac { x^a } { x^b } + \frac { x^c } { x^b }) } +\frac {1} { (1+ \frac { x^b } { x^c } + \frac { x^a } { x^c }) } \)
=\(\frac { X^a } {(X^a+X^b+X^c) }+\)\(\frac { X^b } {(X^a+X^b+X^c) }+\)\(\frac { X^c } {(X^a+X^b+X^c) }\)
=\(\frac { (X^a+X^b+X^c)} {€‹€‹(X^a+X^b+X^c )}\)
=1
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