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Discussion :: Problems on Trains

  1. Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

    2. A.
    12 sec
    B.
    24 sec
    C.
    48 sec
    D.
    60 sec

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    Answer : Option B

    Explanation :

    Relative speed = = (45 + 30) km/hr
     
    = 1-sym-oparen-h1 75 x 5 1-sym-cparen-h1 m/sec
    18
     
    = 1-sym-oparen-h1 125 1-sym-cparen-h1 m/sec.
    6

    We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

    So, distance covered = Length of the slower train.

    Therefore, Distance covered = 500 m.

    Therefore Required time = 1-sym-oparen-h1 500 x 6 1-sym-cparen-h1 = 24 sec.

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