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  1. A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

    2. A.
    48 km/hr
    B.
    54 km/hr
    C.
    66 km/hr
    D.
    82 km/hr

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    Answer : Option D

    Explanation :

    Let the speed of the second train be x km/hr.

    Relative speed = (x + 50) km/hr
     
    = 1-sym-obracket-h1 (x + 50) x 5 1-sym-cbracket-h1 m/sec
    18
     
    = 1-sym-obracket-h1 250 + 5x 1-sym-cbracket-h1 m/sec.
    18

    Distance covered = (108 + 112) = 220 m.

    Therefore 220 = 6
    1-sym-oparen-h1 250 + 5x 1-sym-cparen-h1
    18

    => 250 + 5x = 660

    => x = 82 km/hr.

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