Menu
Home / Arithmetic Aptitude / Problems on Ages :: Discussion

Discussion :: Problems on Ages

  1. Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
    2. A.

    2 times
    B.

    2\( \frac { 1 } { 2 } \)times
    C.

    2\( \frac { 3} { 4 } \)times
    D.

    3 times

    View Answer

    Workspace

    View Answer

    Answer : Option A

    Explanation :

    Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

     

    (4x + 8) =\( \frac {5 } { 2 } \)(x + 8)

     

     8x + 16 = 5x + 40

     

     3x = 24

     

     x = 8.

     

    Hence, required ratio =\(\frac { (4X+16 )} { (X+16 )}=\)\( \frac { 48 } { 24 }\)=2

     

Write your comments here:

Be The First To Comment