Discussion :: Probability
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What is the probability of getting a sum 9 from two throws of a dice?
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A.
\(\frac { 1 } { 6 }\) |
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B.
\(\frac { 1 } { 8 }\) |
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C.
\(\frac { 1 } { 9 }\) |
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D.
\(\frac { 1 } { 12 }\) |
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Answer : Option C
Explanation :
In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E)= \( \frac { n(E) } { n(s)}\)=\(\frac { 4 } { 36 }\)=\(\frac { 1 } { 9 }\)
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